x^2/(0.8-x)(0.4-x)=9

Solution for x^2/(0.8-x)(0.4-x)=9 equation:

x^2/(0.8-x)(0.4-x)=9

We move all terms to the left:

x^2/(0.8-x)(0.4-x)-(9)=0


Domain of the equation: (0.8-x)(0.4-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.4-x!=-0.8

x∈R


We add all the numbers together, and all the variables

x^2/(-1x+0.8)(-1x+0.4)-9=0

We multiply parentheses ..

x^2/(+x^2-0.4x-0.8x+0.32)-9=0

We multiply all the terms by the denominator


x^2-9*(+x^2-0.4x-0.8x+0.32)=0

We multiply parentheses

x^2-9x^2-0x-0x-2.88=0

We add all the numbers together, and all the variables

-8x^2-2x-2.88=0

a = -8; b = -2; c = -2.88;
Δ = b2-4ac
Δ = -22-4·(-8)·(-2.88)
Δ = -88.16
Delta is less than zero, so there is no solution for the equation